[gl-como] Quesito...

[Damiano Venturin]

On Fri, 2005-04-01 at 15:38 +0200, Brisa Francesco wrote:
> non molto difficile, direi:
> 
> -x*x-x+4+y>0
> x+5/2>0
> 16/10->0
> ((x-0.8)2+(y-1.6)2-0.44) != 0
> 
> anche:
> log(-x*x-x+4-y)!=0   ->  -x*x-x+4-y !=1
> log(16/10-x)!=0  ->  16/10-x != 1
> 
brisa rules ;)